An inductor has inductance of 0.340H and carries a current that is decreasing at a uniform rate of 17.0 mA/s. find the self induced emf in this inductor .
The voltage/current relation across an inductor is given by V(t) L dI/dt in this case, dI/dt is 17 mA/s, thus the self-induced emf is V 0.34*17 5.78 mV
