There are two questions i need help on?PLEASEWhat is a sample of a 2nd period element that has 8 electrons in its outer shell?And calcium reacts with aluminum chloride to produce aluminum and calcium chlorideBring the amount of aluminum produced from 50 grams of calcium
I love that stuff!!! But I think it's pretty high in sugar so I stick to oatmeal.
Neon is the first answerThe second answer: 3Ca(s) + 2AlCl3 - 2Al(s) + 3CaCl2 50g Ca1.25 moles Ca 1.25/3 20.8333333 moles Al 22.5g Al 23g Al (to 2 significant figures)- Explanatory details (if you need them) - The process: For Q1 - All the elements in Group 18, (those on the farthest right of the periodic table), have full 'octet' outer shells, that is, they have 8 electrons in their outer shellsThey are the noble gasesThey are very stableAll other atoms attempt to attain the noble gas electronic configuration, by means of bondingPeriods are horizontal, groups are verticalSo the 2nd period, begins with Li and ends at Ne or NeonFor Question 2 Consider the charges on each ion Ca2+, Al3+, Cl-So Al3+ + Cl- (to form aluminium chloride) will have the formula AlCl3Calcium chloride is CaCl2Writing the equation out with states represented, as in, (s) for solid etc Ca(s) + AlCl3 - Al(s) + CaCl2(s) We can see the equation needs to be balancedIts balanced for Ca, but the LHS (left hand side) has 2 Cl, but the RHS has 3So we tinker and find: 3Ca(s) + 2AlCl3 - 2Al(s) + 3CaCl2 to be balancedWe have 50g CalciumConvert to moles by the formula nm/M (moles mass of substance/Molar Mass of substance) 50g/40g 1.25 molesThe ratio between Ca and Al, as seen in the equation, is 3:2So to find the amount of Al, we need the moles of AlSo, 1.25/3, 2 and we have 0.8333333 moles of AlMultiply by the molar mass (26.98g/mol) and we have our answerThen since the question has only two significant figures (50g Calcium), we reduce our answer to two significant figures, ie, 23g Al
I love that stuff!!! But I think it's pretty high in sugar so I stick to oatmeal.
Neon is the first answerThe second answer: 3Ca(s) + 2AlCl3 - 2Al(s) + 3CaCl2 50g Ca1.25 moles Ca 1.25/3 20.8333333 moles Al 22.5g Al 23g Al (to 2 significant figures)- Explanatory details (if you need them) - The process: For Q1 - All the elements in Group 18, (those on the farthest right of the periodic table), have full 'octet' outer shells, that is, they have 8 electrons in their outer shellsThey are the noble gasesThey are very stableAll other atoms attempt to attain the noble gas electronic configuration, by means of bondingPeriods are horizontal, groups are verticalSo the 2nd period, begins with Li and ends at Ne or NeonFor Question 2 Consider the charges on each ion Ca2+, Al3+, Cl-So Al3+ + Cl- (to form aluminium chloride) will have the formula AlCl3Calcium chloride is CaCl2Writing the equation out with states represented, as in, (s) for solid etc Ca(s) + AlCl3 - Al(s) + CaCl2(s) We can see the equation needs to be balancedIts balanced for Ca, but the LHS (left hand side) has 2 Cl, but the RHS has 3So we tinker and find: 3Ca(s) + 2AlCl3 - 2Al(s) + 3CaCl2 to be balancedWe have 50g CalciumConvert to moles by the formula nm/M (moles mass of substance/Molar Mass of substance) 50g/40g 1.25 molesThe ratio between Ca and Al, as seen in the equation, is 3:2So to find the amount of Al, we need the moles of AlSo, 1.25/3, 2 and we have 0.8333333 moles of AlMultiply by the molar mass (26.98g/mol) and we have our answerThen since the question has only two significant figures (50g Calcium), we reduce our answer to two significant figures, ie, 23g Al
