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Help balancing chemistry equation Aluminum metal reacts with hydrochloric acid, HCl, to form hydrogen gas?

Aluminum metal reacts with hydrochloric acid, HCl, to form hydrogen gas (H2) and a solution of aluminum chloride. Write and balance the equation. Can someone help I just dont get this Al2 + 6HCl → 3H2 + 2AlCl3 Al2 + 2HCl → H2 + 2AlCl 2Al + 6HCl → 3H2 + 2AlCl3 Al + 2HCl → H2 + AlCl2 6Al + 2HCl → H2 + 2Al3Cl

Answer:

Aluminum reacts with HCl ... This is a single replacement reaction in which aluminum replaces hydrogen ion. Aluminum metal is oxidized by H+, and H+ is reduced by aluminum metal. Chloride ion is a spectator ion. You also need to know that aluminum usually exhibits a +3 oxidation state. This means that there will be three chloride ions (oxidation number of -1) for each aluminum. 2Al(s) + 6HCl(aq) -- 2AlCl3(aq) + 3H2(g)
2NH4Cl+Ca(OH)2-CaCl+2NH3+2H2O 18 Zn+2Cl-ZnCl2+H2 19 F2+2NaCl-2NaF+Cl2 20 CaO+SO2-CaSO3 21 2CaSO3+O2-2CaSO4 22 2HgO-2Hg+O2 23 CH3OH-CO+2H2 24 2KNO3-2KNO2+O2 you put the question in wrong section. Answer the others by yourself. I have given lots of examples there.
this is an oxidation reduction reaction it has to be belanced has one so first you need to calculate the oxidation numbers (o.n.) of the species: eq: Al(s) + HCl → H2 (g) + AlCl3 o.n.: 0......+1 -1 ......0......... +3 -1 The oxidation number of H changes of +1 to 0 so its a reduction reaction. The oxidation number of Al changes of 0 to +3 so its a oxidation reaction. calculate the balanced equation (Al(s) → AlCl3 + 3e-) x 2 (2e- + 2HCl → H2) x 3 --------------------------------------... 2Al(s) + 6HCl → + 2AlCl3 + 3 H2
Aluminum And Hydrochloric Acid
This Site Might Help You. RE: Help balancing chemistry equation Aluminum metal reacts with hydrochloric acid, HCl, to form hydrogen gas? Aluminum metal reacts with hydrochloric acid, HCl, to form hydrogen gas (H2) and a solution of aluminum chloride. Write and balance the equation. Can someone help I just dont get this Al2 + 6HCl → 3H2 + 2AlCl3 Al2 + 2HCl → H2 + 2AlCl 2Al + 6HCl → 3H2 + 2AlCl3 Al + 2HCl → H2 + AlCl2...

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