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Question:

How do you calculate output power in an AC Three phase Induction Motor?

Load=0.5Nminput voltage=397VAmps= 1.77Power Factor=0.66Input Power= 762 WattsSpeed= 1422rev per min or 148.91 rad per minthese are all the values i have

Answer:

Output power = 1.732(397)(1.77)(0.66) = watts
P=IE
It can be shown mathematically that The total instantaneous power for a balanced 3-phase system is constant and is equal to 3 times the average power per phase.” That means that the rotating stator and rotor magnetic fields in a three phase motor are not pulsating at all as they are in a single phase motor. Edit 1 I would agree that size, fan etc. probably have more to do with the differences in sound than 1ph vs 3ph, but I suspect this is an academic question that should have been preceded by all other things being equal.
Three Phase Induction Motor Calculations
in three phase circuit input power is P=V*I*sqrt(3) output power is P=V*I*sqrt(3)*cos(theta) V=voltage (effective voltage) I=current (RMS current) sqrt(3) = 1.73.... (square root of three) cos(theta) = power factor based on given voltage and current values, input power is 1215W while output power is 802W we can also calculate same using mechanics: P=T*w where T is torque and w is angular velocity (rad/sec) 1422RPM is 149 rad/sec and with only 0.5Nm torque power is only 75W so your numbers don't match. are you reading current and voltage of the name plate or those are actual measurements? if the load is smaller, motor will draw less current (less than FLA listed on name plate).

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