how many electrons are available for bonding in AlCl3?
low carb depends on what phase you are onInduction is 20 gramsthen you start to move upwards from there.
NoneHere is how you know: If you're unfamiliar with the tricks to using the periodic table, the number in the ones column of the group for any element (These run across the top horizontally) is the number of valence electrons in its outer shellGoing to assume you understand electron shell theory, if not you'll need to consult a diagram a chapter or so back in your bookElectron shells really like to be filledAluminum has 3 valence electronsOut of a possible 8, this is closer to 0 than 8It wants to share those electrons, giving it a positive charge (Easier to ditch 3 than pick up 5)Chlorine has 7 Valence electrons7 is closer to 8, so it's easier to want to pick up 1 more electron to fill its shell, giving it a negative chargeSo, when you have 1 Aluminum atom, and 3 Chlorine atoms, you end up with +3 from Al and -3 from ClThe charge balances, they share their electrons, and the electron shell fills Certain elements have more than one possible number of valence electrons, such as Fe2 and Fe3, etcJust an FYI, not important to the question asked.
