I need to have a speed reducer drives a crank link system, through the calculation of the maximum load for the crank system I need to choose the reducer output torque of 400N.m. is bigger than 400N.m? Or to first calculate the load multiplied by a safety factor of 1.6 for 400*1.6=640N.m, and then select the output torque of reducer about more than 640N.m?
If you run the linkage system more stable, there is no need to add the coefficient, because the reducer itself has the overload coefficient, and coefficient is: working machine is more complex, but with a peak load.Of course, I'm on the safe side. I suggest you choose the 1.1~1.2 of the maximum load on the connecting rod when you select the torque output of the reducer.
The reducer is a kind of independent parts enclosed by a rigid shell gear, worm gear, gear - worm gear reducer, commonly used as a prime mover and work machine. It plays an important role in matching speed and transmitting torque between prime mover and working machine or actuator, and it is widely used in modern machinery.
Reducer in the prime mover and working machine or actuator between the matching speed and torque transfer role, reducer is a relatively precise machine, the purpose of using it is to reduce speed, increase torque.
If the operation is relatively stable link system, there is no need to add the coefficient, because the reducer itself has the overload coefficient, and coefficient is: working machine is more complex, but with a peak load. It is recommended to select the 1.1~1.2 of the maximum load of the connecting rod system when selecting the output torque of the reducer.
