Aluminum reacts with chlorine gas to form aluminum chloride via the following reaction: 2Al (s)+3Cl_2 (g)#92;rightarrow2AlCl_3(s)What is the maximum mass of aluminum chloride that can be formed when reacting 29.0 g of aluminum with 34.0 g of chlorine?
2 Al + 3Cl2 -- 2AlCl3 29 grams of Aluminium , 34 grams of Chlorine Atomic weight of Aluminium = 27 Atomic weight of Chlorine = 35.5 Therefore 29 / 27 (= 1.074) gram moles of aluminium atoms are available to react with 34 / 35.5 (= 0.958) gram moles of chlorine atoms BUT 3 times more chlorine atoms are required for this reaction than aluminium atoms therefore, only 0.958 / 3 (= 0.319) gram moles of aluminium can be consumed by the reaction to produce 0.319 gram moles of Aluminium chloride. The molecular weight of Aluminium chloride = 27 + (3 x 35.5) = 133.5 Therefore the maximum mass of Aluminium chloride that can be formed = 133.5 x 0.319 = 42.6 grams of Aluminium chloride
