how do you expand this??question: Expand the brackets1/2(n-1)(n-2)3
i think its 1/2n-1/2 3n-6
1/2(n-1)(n-2)3 (1/2n-1/2) (3n-6) 3/2n^2-3n-3/2n+3 3/2n^2-9/2n+3
If the terms with the brackets are on the bottom: 1/2(n-1)(n-2)3 1/(6(n^2-3n+2)) 1/(6n^2 -18n + 12). If you mean (1/2)(n-1)(n-2)3 (3/2)(n^2-3n+2) (3/2)n^2 - (9/2)n + 3.
