Can you please help me about this question?
This is an absurd question, as the source resistance of the step input source e(t) is shown as zero.In that case, the source will dictate the voltage across C and voltage across C will always be equal to source voltage. You could pretend that source has a resistance. In that case, output is a voltage that decays as exp[-t/(RC)] where R is source resistance.It builds up with a much lesser time constant if R of L is very low.
After a large time has passed, for a constant e(t), capacitor current 0 inductor current e(t)/R
