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What is the mass of CaCO3 in the original samplehelp with this problem?

Dolomite is a mineral consisting of calcium carbonate (CaCO3) and magnesium carbonate (MgCO3). When dolomite is strongly heated, its carbonates decompose to their oxides (CaO and MgO) and carbon dioxide is expelled. When a 91.6 g sample of dolomite was strongly heated, a residue of mass 47.6 g remained. What is the mass of CaCO3 in the original sampleWhat is the mass of MgCO3 in the original sample? What is the percentage of CaCO3 in the original sample?What is the percentage of MgCO3 in the original sample

Answer:

first of all i would like to see the code and what is said. It should have said Small EVAP leak if it said anything besides this then it was NOT your gas cap. If this is the case then you need to have the codes cleared with a code scanner. disconnecting the battery DOES NOT reset codes it resets you whole computer system so after you 100 mile drive cycle the light will come back on. MORE INFO NEEDED
From my own experience removing battery WILL reset some cars codes others need 10 or more good starts others NEED resetting, my v70 t5 requires battery to be removed or faults cleared with obd2 reader (apart from airbags and traction/abs faults which require specialist reader) My vauxhall vectra 2.2 direct needed 10 good starts. Is your light a fault light or simply a service reminder?
The problem is that the engine codes that auto zone checks are only part of the diognostic process. You need to have the car check by a qualified mechanic.
CaCO3 → CO2 + CaO MgCO3 → CO2 + MgO All of the weight lost was due to CO2. (91.6 g - 47.6 g) / (44.0096 g CO2/mol) 0.99978 mole CO2 (from both sources) Let z be the mass of CaCO3 in the original sample. Then (91.6 - z) is the mass of MgCO3 in the original sample. Convert both these masses to moles, then add them, which will give the total moles of CO2: (z / 100.0875 g CaCO3/mol) - ((91.6 - z) / (84.3141 g MgCO3/mol)) 0.99978 mole Solve for z: z 46.35 g CaCO3 in the original sample 91.6 - 46.35 45.25 g MgCO3 in the original sample 46.35 / 91.6 50.6% CaCO3 100 - 50.6 49.4% MgCO3

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