a 500v dc shunt motor operating at hoist raise of load 400kg at 2,5m/sec . calculate the current drawn by the?
Work done = mass * acceleration * distance = 400 kg * 9.8 m/s? * 2.5 m = 9800 Joules and this work is done every second (because of the rate 2.5 m PER SECOND). Power = Work/time = 9800 Joules/sec = 9800 Watts Assuming two things (because the question is incomplete: add Additional Details to complete the question). 1. The DC motor is 100% efficient 2. The Shunt magnitization current is negligible compared with the armature current. Power = Volts * Amps 9800 = 500 * Amps Armature Amps = 19.6 .
