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Question:

algebra 2 problem solving 2?

a motorcycle brakes down and the rider has to walk the rest of the way to work. The motorcycle was traveling at 45 mi/hr, and the rider walks as a speed of 6 mi/hr. The distance from home to work is 25 miles, and te total time of the trip was 2 hours, how far did the motorcycle go before it broke down?

Answer:

Don't waste your money on the titanium. Won't be worth the extra money/hp.
MR Motorcycle Rate MT Motorcycle Time MD Motorcycle Distance WR Walking Rate WT Walking Time (MR)(MT) + (WR)(WT) 25 45MT + 6WT 25 MT + WT 2 WT -MT + 2 45MT + 6(-MT + 2) 25 45MT - 6MT + 12 25 39MT 13 MT 1/3 (MR)(MT) MD (45)(1/3) MD MD 15 miles
motorcycle went 1/3 hours 15 miles then onfoot 1 2/3 hours 10 miles from the equation 6x + 45(2 -- x) 25 giving x 5/3 1 2/3 for onfoot.
45x + 6(2-x) 25 45x + 12 - 6x 25 39x 13 x 1/3 He went 1/3 hours (20 minutes) before it broke down, meaning he traveled 15 miles in motorcycle. The rest 5/3 hours (100 minutes) were on foot, meaning he traveled 10 miles on foot.
i would say the titanium because its lighter butt dont waste your money on cold air intake it barely does anything
i would say the titanium because its lighter butt dont waste your money on cold air intake it barely does anything
Don't waste your money on the titanium. Won't be worth the extra money/hp.
MR Motorcycle Rate MT Motorcycle Time MD Motorcycle Distance WR Walking Rate WT Walking Time (MR)(MT) + (WR)(WT) 25 45MT + 6WT 25 MT + WT 2 WT -MT + 2 45MT + 6(-MT + 2) 25 45MT - 6MT + 12 25 39MT 13 MT 1/3 (MR)(MT) MD (45)(1/3) MD MD 15 miles
motorcycle went 1/3 hours 15 miles then onfoot 1 2/3 hours 10 miles from the equation 6x + 45(2 -- x) 25 giving x 5/3 1 2/3 for onfoot.
45x + 6(2-x) 25 45x + 12 - 6x 25 39x 13 x 1/3 He went 1/3 hours (20 minutes) before it broke down, meaning he traveled 15 miles in motorcycle. The rest 5/3 hours (100 minutes) were on foot, meaning he traveled 10 miles on foot.

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