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Help on double pipe parallel heat exchanger?

3.A double pipe parallel flow HE is used to heat cold tap water with hot water. Hot water (cp=4.25 kj/kg C) enters the tube at 85 C at a rate of 1.4 kg/s and leaves at 50C. The HE is not well insulated and it is estimated that 3% of the heat given up by the hot fluid is lost from the HE. IF the OHTC and surface area of the HE are 1150 W/m2C and 4 m2 respectively, determine the rate of Heat transfer to the cold water and the LMTD

Answer:

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Heat Transfer to the Cold Water: Qc = Qh*(1 - 0.03) where: Qh = mh*Cph*dTh = 1.4*4.25*(85-50) = 208.25 kW Qc = 208.25*0.97 = 202.0025 kW LMTD LMTD = Qc/(U*SA) = 202.0025/(1.150*4) = 43.9 C

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