A pendulum clock with a brass suspension system is calibrated so that its period is 1 s at 8?C.If the temperature increases to 39?C, by how much does the period change?Answer in units of s.I mainly just need help setting it up. Thanks in advance :]
I assume you mean the rod is made of brass. The material of the suspension system does not matter. linear thermal expansion coef brass 19e-6 /K ?L/L α?T, α is linear thermal expansion coef ?L/L α?T 19e-6(31?) 589e-6 m/m Pendulum period in seconds T ≈ 2π√(L/g) or, rearranging: g ≈ 4π?L/T? L ≈ T?g/4π? L is length of pendulum in meters g is gravitational acceleration 9.8 m/s? L (1)?(9.8) / 4π? 0.2482369 meters 0.2482369 x 589e-6 0.0001462m new length 0.2483831 m T ≈ 2π√(L/g) 1.000294 or a change of 294 ?s
