A 265 mH inductor whose windings have a resistance of 6.70 Ω is connected across a 10.5 V battery with an internal resistance of 3.35 Ω. How much energy (in J) is stored in the inductor?Thanks for the help!
U Potential energy R Resistance 6.7ohms I current V/R (10.5V/6.7ohms) 1.57A L inductance 265mH .265H U (.5)LI^2 (given formula in any physics text book) U (.5)*(.265H)*(1.57A)^2 .33 J
PI*R^2 (electric power wiki)
