A) Cuddle by the fire with a blanket, a sweater, a book/TV and hot co coB) Go outside in the cold and have fun!I am option A. and ocassionally B
% by using mass of Fe2O3 (mass of organic Fe2O3 / mass of iron ore) x one hundred% mass of Fe2O3 (organic) (mass of iron produced / MW of iron) x ( stoichiometric mole ratio of Fe2O3 over Fe depending on the given chemical reaction x MW of Fe2O3 mass of iron produced 453 g MW of Fe fifty 5.80 5 stoichiometric mole ratio of Fe2O3/Fe a million/2 MW of Fe2O3 159.7 mass of organic Fe2O3 (453/fifty 5.80 5) x (a million/2) x 159.7 mass of organic Fe2O3 647.sixty six grams %by using mass of Fe2O3 (647.sixty six / 752) x one hundred 86.13 %
ok. How did you get 0.626? I understand how were supposed to add it all up and divide the atomic mass of whatever element were working on like Fe for example is 55.845 / the total sum of the atomic masses. In this case 55.845/159.6882 .349712*10034.97% so how is the answer 69.8%? PLEASE EXPLAIN! D
I am waiting for more replies before I post my view
A! I hate being cold, leaving snow on the ground when i come in, getting yelled at, and having a red nose. I am not Rudolph!
