will pounding on the floor set off a smoke detector on the floor below?
many states have a spend down option, where if you spend so much on medical care that your income is down below a certain threshhold, the state will then pay thru their medicaid program. In this case, I think you should be sure he gets inpatient treatment, insurance or no. Right away, as in go to the ER of a community hospital that has an inpatient psych unit. I have bipolar disorder, and have been on 72 hour holds in the hospital and stuff, so I don't say it lightly, that he needs to go inpatient, money or not. If the family has to file bankruptcy, they will still have their home and a semi-decent car. If they have a baby girl, they probably don't have many assets to lose anyhow. I went thru bankruptcy, and it wasn't the end of the world, not really that big a deal honestly (except for the shame, but it was because mental health wasn't covered by insurance). Also, if the hospital sends an outrageous bill, that can be negotiated down by at least 1/3. If the baby had a hole in her heart and insurance didn't cover it, would the family sacrifice to pay for that? Getting care for what is wrong with him is as important as that. He should't be left alone with his wife or his baby. He already knows he has a problem, it is up to your family and his wife's family to relieve the stress here and keep an eye on him, until you get him inpatient, which is an emergency, in my opinion. After he gets out, I would also give him a lot of supervision help with stressful things. Often stress makes mental problems worse. I know this is an awful situation for all of you, but your brother admits he needs help, and you will have to make sure he gets it.
Every half-life, an isotope will lose half of its activity due to radioactive decay. Therefore, you can roughly calculate as: 1 half-life 433 years 50% of the original activity 2 half-lives 866 years 25% 3 half-lives 1299 years 12.5% 4 half-lives 1732 years 6.25% 5 half-lives 2165 years 3.125% 6 half-lives 2598 years 1.5625% 7 half-lives 3031 years 0.78125% Therefore, the source will decay below 1% of its original value in roughly 3000 years. You can calculate the decay exactly as: ln(0.01)/-e^(432.7*365.2422) 1,050,220 days. Therefore, a 1uCi source on December 3rd, 2010 will have 0.01uCi on April 29th, 4886 Ionization smoke detectors are still in use today because they are excellent detectors of fast flaming fires, whereas photoelectric smoke detectors are excellent detectors of slow smoldering fires. The dose one will receive from an ionization smoke detector in one year is less than the average american will receive from all sources (sun, food, granite counter-tops, flying, etc) in one day.
